Sunday, January 20, 2013

Projectile Motion Reflection

     In this week's lab, I learned about projectile motion: how it works and how to analyze it. A projectile is an object in which only the force of gravity is acting upon it. Its general path of motion is a parabolic trajectory.

      Using the Video Physics App on our Ipads, we analyzed the path of motion of a basketball when shot in the air. After taking the video, we plotted points along the ball's path through the air. We then used these points to graph the x and y components of the ball's path.

X-Component

      The top graph shows the x position over time. The change in position over the change in time is also known as the slope. The slope is constant in this case. The bottom graph shows the x velocity over time. Because acceleration is the change in velocity over the change in time and we know that the velocity is also constant, there is no acceleration and no net force.

Y-Component

       The top graph shows the y position over time. The change in position over the change in time is the slope and velocity. The graph shows that the slope is not constant; therefore, the object is accelerating. The bottom graph shows the y velocity over time. The decreasing line crosses the x-axis, and at that moment the object has a velocity of 0, which means it is at its peak. The rest of the time it is decreasing.


Sunday, January 13, 2013

Forces in 2D and Circular Motion

Big Questions

1. What does it mean to analyze forces in 2D?

          Analyzing forces in 2D means that there are two dimensions that need to be measured, an x-component and a y-component, which make up a force at a certain angle. Once we break the two dimensions up, we can use SOH CAH TOA to find the magnitude of Fx and Fy. Then we can find Fnetx and Fnety to calculate the total force. The photo shows an example:


2. How do forces cause objects to move in a circle?

          Centripetal force is a center-pointing force that causes objects to move in a circle. The force and velocity act perpendicular to each other. The object does accelerate; however, it is not the magnitude that changes, but the direction. The magnitude remains at a constant speed, but the direction keeps changing. Without this centripetal force, an object would continue to move in a straight line, tangent to the circle. In the hover disk lab we did this week, we spun the disk connected to a rope in a circle at a constant speed. When we let go, the disk continued moving, but in a straight line since there was no centripetal force.



3. What does it mean to be an orbit? How do satellites orbit planets? How do planets orbit the sun?

          In the hover disk lab, the disk orbits the person, just as satellites orbit planets and planets orbit the sun. When something is in orbit, it is constantly moving around another object in a circle. When satellites orbit planets, the centripetal force acting on them is gravity, pulling them to the center. A satellite in space is actually moving at a free-fall toward the planet. The satellite moves in a sideways direction and falls into orbit. The planets orbit the sun in the same way.




Sunday, November 18, 2012

Newton's Three Laws of Motion

Over the past 2 weeks, we have been deriving Newton's three laws of motion by performing the hover disk lab and the fan cart lab.

Newton's First Law
  • An object at rest or traveling at a constant speed will continue to do so, unless a net force acts on it.
  • Any object moving at a constant speed or at rest, has no net force acting on it. (Fnet = 0). The hover disk lab allowed us to see how this law works. When the hover disk is at rest or moving at a constant speed, it will not have a change in velocity, or accelerate, because there is no net force acting on it.
  • Although there is no net force acting on the object because the object is at rest, there are still many forces acting on everything. In the interaction diagram, you can see that there is a gravitational force acting down on person 1, person 2, the earth, and the hover disk. But what allows them to not fall through the ground is the normal force acting up on them.
  • Here is an example where the object remains at a constant speed. Here we see that there is so net force on the object; however, there are still gravitational and normal forces acting on oerson 1, person 2, the disk, and the earth.

Newton's Second Law
  • Force = mass (acceleration)
  • From the fan cart lab, we derived this equation. We measured the acceleration of a 0.3 kg fan cart when turned on high with a constant force of 0.15 newtons. We then added weights of different masses to the fan cart to find different accelerations. From this we found that acceleration is the change in velocity divided by the change in time.
Collected Data

0.3 kg cart: 0.450 m/sec^2

0.4 kg cart: 0.380 m/sec^2

0.6 kg cart: 0.208 m/sec^2

1.1 kg cart: 0.146 m/sec^2

1.4 kg cart: 0.123 m/sec^2

1.7 kg cart: 0.105 m/sec^2


  • To derive this equation, we found that as the mass increases, the acceleration decreases, meaning that mass and acceleration are inversely proportional. We also had to take into account that the force remains constant; therefore, we came up with the equation F = ma.

Newton's Third Law
  • When two objects interact, they exert equal and opposite forces on each other.
    • These forces are:
      • equal in magnitude
      • opposite in direction
      • same type of force
  • The hover disk lab helped us see how this law is true. When the hover disk is moving with a net force and is stopped by person 1's hand, the disc and the hand with exert and equal but opposite force on each other, which will be a normal force. 


Real World Connection

Here is a website that tells how Newton's laws of motion relate to a dancer.

http://physicsofballet.homestead.com/newtonlaws.html



Sunday, October 28, 2012

Impulse Lab

Introduction
In this week's lab we crashed an empty red cart into a force-probe with aluminum (to slow down time) attached to a ring stand. We found the velocity of the cart before and after the collision. We then found the change in momentum, also known as impulse. We did this to measure the relationship between impulse, force, and time during a collision.
cart with aluminum
force prob with aluminum


Key Info

  • impulse: a change in momentum (another way of representing the conservation of momentum)
  • impulse is measured in Joules
  • momentum = P
  • impulse equation: J = Pfinal - Pinitial
  • mass of car: 0.25 kg
  • velocity is measured in meters per second (m/s)



Big Question
What is the relationship between impulse, force, and time during a collision?




After we collided the car with the aluminum ring, we found the velocity of the cart in the collision before and after using the sonic range finders. Then we found the momentum before and the momentum after to find the impulse. Then we recorded the area, also known as the integral, under the Force vs. Time graph. 



Here is what our data looked like:


From here, we did the calculations and found that the area of a force vs. time graph is impulse. So now the equation for impulse can be written as Impulse = Force (Time) or J = F(t).

Analyzing Data


Concluding Ideas
       Impulse and Are are the same! After determining the area of a Force vs. Time graph and calculating the impulse, the answers come out to be equal. Forces are equal and opposite; therefore, the impulse remains constant in a collision by increasing the time and decreasing the force. In the collision, the metal sheets increased the time and decreased the force.

Real Life Connection
        Boxing uses this same principle of minimizing the effect of a force by extending the time of the collision. When a boxer recognizes that he will be hit in the head by his opponent, the boxer often relaxes his neck and allows his head to move backward upon impact. This known as "riding the punch." A boxer rides the punch in order to extend the time of impact of the glove with their head. Extending the time results in decreasing the force and then minimizing the effect of the force in the collision. Now that is physics in action!
  
Here's a clip from the final fighting scene in the movie Rocky Balboa 


Saturday, October 13, 2012

Collisions Lab

The BIG Question
   
    What is the difference between the amount of energy lost in an elastic collision vs. inelastic collision?
    What is a better conserved quantity- momentum or energy?

Background

    • scalar quantities: magnitude (mass, energy, temperature)
    • vector quantities: magnitude and direction ( + rightward, - leftward)
    • types of collisions:
      • elastic- objects bounce off each other
      • inelastic: objects stick together
    • momentum: p = m (v)
      • mass (velocity)
      • mass is measured in kilograms (kg)
      • velocity is measured in meters per second (m/s)


  • In this week's lab, our goal was to find the difference between the amount of energy lost in an elastic collision and inelastic collision. To test this, we put two cars of the same mass on opposite sides of a track, one red and one blue. We set two range finders on the ends of the track, which measure the velocity of the cars. These range finders were plugged into the electronic force probe, which was then plugged into the computer. The application on the computer graphed the velocity of both cars before, during, and after the collision.
  • For the inelastic collision, we pushed the red car to the right toward the blue car, which then stuck together with velcro. Both cars continued to move together to the right. 
  • For the elastic collision, we pushed the red car with a spring toward the blue car to the right. In this collision, the red car followed the blue car at a much slower pace once they hit, while the blue car continued to move to the right.
  • We recorded our data and found the total momentum (p = mv) and the total kinetic energy (KE = 1/2mv^2) of both collisions.


  • Then we found the percent difference of both the amount of energy and momentum that left or entered the system for both elastic and inelastic collisions.
    • Percent difference: 
      • Kinetic energy: (Total after - Total before)/(Total after + Total before / 2) (100)
      • Momentum: (Total after - Total before)/(Total after + Total before / 2) (100) 


  • We found that momentum is a better conserved quantity rather than energy because more energy is given off during a collision. Momentum has a smaller percent difference.
  • We also found that inelastic collisions lose more energy than elastic collisions

Real Life Connection: 
      The game of pool uses the exact same concepts of momentum in collisions. When the white ball hits another colored ball, the hit and the colored ball keeps moving. The goal of the game is to get all the colored balls in the holes without knocking the white ball in with them. The velocity of the balls plays a key part in strategizing. 

       

Sunday, September 30, 2012

Rubber Band Cart Launcher Lab

The BIG Question
      How are energy and velocity related?


  • In Physics class this week, we tested to see how energy and velocity are related. To do this, we launched a glider at different distances on an air track. We measured the velocity using a Photogate Sensor, which detects the speed of the glider as it passes through. It works by creating an infrared beam and timing how long this beam is blocked by the glider. In order to get the most accurate data we possibly could, we leveled out the air track so that there no spontaneous movement of the glider. By turning the screw under the air track, we leveled the slope of the air track to make it flat.
  • During the experiment we measured the velocity at 5 amounts of the rubber band stretched. Here are our calculations and data:                                                                                                                          



  • Then we graphed our data using our Graphical Analysis App on our Ipads. Here's what our graph looked like:

  • Post Analysis Questions:
    1. The mass of the red cart is 0.38kg. How do you think the slope and the mass of the glider relate? 
      • We found that the slope of the line, 0.147 v^2/J, is about 1/2 the mass of the cart. 
    1. Can you derive an equation relating energy (KE), mass (m, and velocity (v^2)?
      • To find our equation, we started the y = mx +b, the equation of a line. Then we plugged in the information we had with the variables we're supposed to use and got KE = .147 (v^2) + 0. Then using the answer to our first analysis question, we saw that mass has to be related. So we plugged 1/2 (mass) in for the slope and got KE = 1/2 (m) (v^2) as our final equation.
  • Real Life Connection: In physics, the phrase "kinetic energy" is used to describe the energy of motion. Any object in motion possesses kinetic energy, and this energy can be controlled, transferred, and transformed to do work. A dancer holds much kinetic energy. Moving in a constant direction creates momentum. Momentum is mass in motion. The amount of momentum depends on the amount of mass moving and how fast that mass is moving. This shows how much or how little a dancer can have while performing. Momentum and speed, or mass and velocity, make up kinetic energy in a dancer.

Sunday, September 23, 2012

Rubber Band Lab

The BIG Question??
    - How can we store energy to do work for us later?
    - How does the force it takes to stretch a rubber band depend on the AMOUNT by which you stretch it?


 














  • This week in Physics class, we tested how we are able to store energy that allows work to be done later. To test this, we used a rubber band and an air track that hooks up to an air vacuum. We took two trials, one with a single loop and another with a dooble loop. In order to answer our second big question, we had to measure the force in terms of distance. Once we put the rubber band on the air track, we hooked the electric force probe over both strands of the rubber band. Then we stretched the rubber band five different lengths and held it there for about ten seconds. To calculate the force, we averaged the values using "analyzing statistics." Then we recorded our data and repeated this process for both trials.
    • Trial #1 with single loop:
      • 1) 1 cm = 0.01 m = 0.538 N
      • 2) 2 cm = 0.02 m = 1.341 N
      • 3) 3 cm = 0.03 m = 1.710 N
      • 4) 4 cm = 0.04 m = 2.693 N
      • 5) 5 cm = 0.05 m = 3. 372 N
    • Trial #2 with double loop:
      • 1) 1 cm = 0.01 m = 3.835 N
      • 2) 2cm = 0.02 m = 6. 375 N
      • 3) 3cm = 0.03 m = 8.605 N
      • 4) 4cm = 0.04 m = 11.313 N
      • 5) 5cm = 0.05 m = 12.782 N
  • In order to analyze our data, we graphed these points on a line graph for Trial #1. The force, measured in Newtons, went along the y-axis, and the amount of stretch, measured in meters, along the x-axis.


  • Once we graphed our data, we had to derive an equation from y = mx + b, using the variables F, K, and X.  So we found the slope of our line, which was 70.85 (Newtons/Meters). We found that the slope of our line is our elastic constant "K". We found that Force (F) and the distance stretched (X) were directly proportional. Then we plugged in variables and got F = KX.
  • Now we had to find the energy. As we saw in the Pulley Lab, to find the energy, we need to find the area of a certain part on our graph. In the Pulley Lab we found the area of a rectangle (A = LH) or (W = FD). Now in this lab, we have one line, so to find the area we created a triangle from that one line, using it  as our hypotenuse.
  • The area of a triangle is A = (1/2) BH. To relate the equation to our experiment, We plugged in "U" for "A" which stands for the elastic potential energy. The base of our triangle is "X", the distance stretched, and the height would appear to be Force "F"
    • U = (1/2)  XF
  • Since we already found what the equation for Force is, all we have to do is plug that equation in for F in our new equation.
    • U = (1/2)  X (KX)
    • or U = (1/2)  K (Xsquared)
  • In conclusion, we found that potential energy is the energy stored that does work for us later. In this case, as we pull back the rubber band, potential energy is stored, which enables us to flig the rubber band after we let go.
  • Watch this video about potential energy!

  • Real World Connection: Ever jump on a trampoline before?? If you have, ever wonder what allows you to jump so high? Trampolines contain springs in them. When pressed down upon, elastic potential energy is stored and it releases. It allows you to jump higher and higher and you put more force on the trampoline. Elastic potential energy is what makes a trampoline so fun to be on!